What is the solution for (dy)/(dx)(y^{-2})+y^{-1}=2x ?

The solution for (dy)/(dx)(y^{-2})+y^{-1}=2x is y= 1/(2x+2+c_{1)e^x}

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(dy)/(dx)(y^{-2})+y^{-1}=2x

\frac{d y}{d x} (y^{- 2}) + y^{- 1} = 2 x

y = \frac{1}{2 x + 2 + c _{1} e ^{x}}

Solution steps

\frac{d y}{d x} (y^{- 2}) + y^{- 1} = 2 x

Solve Bernoulli ODE:

y = \frac{1}{2 x + 2 + c _{1} e ^{x}}

y = \frac{1}{2 x + 2 + c _{1} e ^{x}}

\frac{d}{d x} (2 9^{x})

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\frac{d y}{d x} + \frac{1}{x} y = 6 x^{2}

f (x) = \frac{1}{( 1 + x ^{2} )}, at x = - 1

What is the solution for (dy)/(dx)(y^{-2})+y^{-1}=2x ?
The solution for (dy)/(dx)(y^{-2})+y^{-1}=2x is y= 1/(2x+2+c_{1)e^x}