What is (\partial)/(\partial y)(xe^y+cos(y)) ?

The answer to (\partial)/(\partial y)(xe^y+cos(y)) is xe^y-sin(y)

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(\partial)/(\partial y)(xe^y+cos(y))

\frac{\partial}{\partial y} (x e^{y} + cos (y))

x e^{y} - sin (y)

Solution steps

\frac{\partial}{\partial y} (x e^{y} + cos (y))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x e^{y}) + \frac{\partial}{\partial y} (cos (y))

\frac{\partial}{\partial y} (x e^{y}) = x e^{y}

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= x e^{y} - sin (y)

\frac{\partial}{\partial y} (\frac{3 x ^{2}}{y})

x \to 5 + lim (\frac{1}{( x - 5 ) ^{2}})

f (x) = \frac{1 + x}{1 - x}

x \to 1 lim (e^{4 x^{2} - 4 x})

\int x^{2} 2 x + 3 d x

What is (\partial)/(\partial y)(xe^y+cos(y)) ?
The answer to (\partial)/(\partial y)(xe^y+cos(y)) is xe^y-sin(y)