What is the derivative of 1+6sqrt(x) ?

The derivative of 1+6sqrt(x) is 3/(sqrt(x))

What is the first derivative of 1+6sqrt(x) ?

The first derivative of 1+6sqrt(x) is 3/(sqrt(x))

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\frac{d}{d x} (1 + 6 x)

\frac{3}{x}

Solution steps

\frac{d}{d x} (1 + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (6 x)

\frac{d}{d x} (1) = 0

\frac{d}{d x} (6 x) = \frac{3}{x}

= 0 + \frac{3}{x}

Simplify

= \frac{3}{x}

x - 2

\frac{d}{d x} (\frac{x}{x + y})

\frac{2}{ln ( x )}

x \to 2 lim (\frac{x ^{2} + 2}{x - 2})

\int_{0}^{2} - 2 x 4 - x^{2} d x

What is the derivative of 1+6sqrt(x) ?
The derivative of 1+6sqrt(x) is 3/(sqrt(x))
What is the first derivative of 1+6sqrt(x) ?
The first derivative of 1+6sqrt(x) is 3/(sqrt(x))