What is the limit as x approaches+1+of 5/(x^3-1) ?

The limit as x approaches+1+of 5/(x^3-1) is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches+1+of 5/(x^3-1)

x \to + 1 + lim (\frac{5}{x ^{3} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{5}{x ^{3} - 1})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x^{3} - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\frac{d}{d x} (\frac{1}{1 - sin ( x )})

f (x) = 8 x + 2 x^{2} - x^{3}, g (x) = 0

\int \frac{sec ( y )}{co tan ( y )} d y

2 x y y^{^{'}} = y^{2} - x^{2}

h \to 0 lim (- 2 x - h + 4)

What is the limit as x approaches+1+of 5/(x^3-1) ?
The limit as x approaches+1+of 5/(x^3-1) is infinity