What is the derivative of 3x^2+2/x ?

The derivative of 3x^2+2/x is 6x-2/(x^2)

What is the first derivative of 3x^2+2/x ?

The first derivative of 3x^2+2/x is 6x-2/(x^2)

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\frac{d}{d x} (3 x^{2} + \frac{2}{x})

6 x - \frac{2}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x^{2} + \frac{2}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{2}{x})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

= 6 x - \frac{2}{x ^{2}}

\frac{d}{d x} (2 x - y)

\int x^{2} - y^{2} d x

x \to 2 + lim (\frac{x}{x - 2})

x \to 4 lim (3 x - 1)

\frac{d}{d x} (\frac{5 x}{7 + x})

What is the derivative of 3x^2+2/x ?
The derivative of 3x^2+2/x is 6x-2/(x^2)
What is the first derivative of 3x^2+2/x ?
The first derivative of 3x^2+2/x is 6x-2/(x^2)