What is the integral from 0 to 1 of 3/(sqrt(1-x^2)) ?

The integral from 0 to 1 of 3/(sqrt(1-x^2)) is (3pi)/2

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integral from 0 to 1 of 3/(sqrt(1-x^2))

\int_{0}^{1} \frac{3}{1 - x ^{2}} d x

\frac{3 π}{2}

Decimal Notation

4.71238 \dots

Solution steps

\int_{0}^{1} \frac{3}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 3 [arcsin (x)]_{0}^{1}

Compute the boundaries:

\frac{π}{2}

= 3 \cdot \frac{π}{2}

Simplify

= \frac{3 π}{2}

f (x) = 3 x + 3 x

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What is the integral from 0 to 1 of 3/(sqrt(1-x^2)) ?
The integral from 0 to 1 of 3/(sqrt(1-x^2)) is (3pi)/2