What is (\partial)/(\partial x)(2sin(xy)) ?

The answer to (\partial)/(\partial x)(2sin(xy)) is 2cos(xy)y

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(\partial)/(\partial x)(2sin(xy))

\frac{\partial}{\partial x} (2 sin (x y))

2 cos (x y) y

Solution steps

\frac{\partial}{\partial x} (2 sin (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial x} (x y)

= cos (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= 2 cos (x y) y

f (x) = - x^{3} + 15 x^{2} - 48 x + 450

x \to 1 lim (- \frac{2}{x ^{2} - 1})

\frac{\partial}{\partial x} (\frac{x ^{2}}{x ^{2} - 1})

f (x) = 4 x, at x = 1

\frac{\partial}{\partial x} (2 x^{2} - 16 x + y^{2} + 1)

What is (\partial)/(\partial x)(2sin(xy)) ?
The answer to (\partial)/(\partial x)(2sin(xy)) is 2cos(xy)y