What is the integral from-9 to-7 of 1/x ?

The integral from-9 to-7 of 1/x is ln(7)-2ln(3)

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integral from-9 to-7 of 1/x

\int_{- 9}^{- 7} \frac{1}{x} d x

ln (7) - 2 ln (3)

Decimal Notation

- 0.25131 \dots

Solution steps

\int_{- 9}^{- 7} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{- 9}^{- 7}

Compute the boundaries:

ln (7) - 2 ln (3)

= ln (7) - 2 ln (3)

\int_{0}^{1} \frac{3}{x ( x + 1 )} d x

\int e^{- 3 x^{2}} d x

\int 4 x sin (2 x) d x

(- 3, - 4), (0, 2)

\int \frac{1}{10 x ^{3}} d x

What is the integral from-9 to-7 of 1/x ?
The integral from-9 to-7 of 1/x is ln(7)-2ln(3)