What is (\partial)/(\partial x)(2xsin(y-z)) ?

The answer to (\partial)/(\partial x)(2xsin(y-z)) is 2sin(y-z)

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(\partial)/(\partial x)(2xsin(y-z))

\frac{\partial}{\partial x} (2 x sin (y - z))

2 sin (y - z)

Solution steps

\frac{\partial}{\partial x} (2 x sin (y - z))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 sin (y - z) \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 2 sin (y - z) \cdot 1

Simplify

= 2 sin (y - z)

\frac{3 e ^{(- 2 s)}}{( s ^{2} + 2 s + 5 )}

\int \frac{3 x ( 2 )}{( x )} d x

\frac{d}{d x} (\frac{ln ( x )}{x})

\int_{0}^{1} \frac{5}{1 + t ^{2}} d t

\int x^{5} (x^{6} + 5)^{5} d x

What is (\partial)/(\partial x)(2xsin(y-z)) ?
The answer to (\partial)/(\partial x)(2xsin(y-z)) is 2sin(y-z)