What is the integral of 8e^{7x} ?

The integral of 8e^{7x} is 8/7 e^{7x}+C

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integral of 8e^{7x}

\int 8 e^{7 x} d x

\frac{8}{7} e^{7 x} + C

Solution steps

\int 8 e^{7 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int e^{7 x} d x

Apply u-substitution

: \int e^{u} \frac{1}{7} d u

= 8 \cdot \int e^{u} \frac{1}{7} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \frac{1}{7} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 8 \cdot \frac{1}{7} e^{u}

Substitute back

u = 7 x

= 8 \cdot \frac{1}{7} e^{7 x}

Simplify

8 \cdot \frac{1}{7} e^{7 x} : \frac{8}{7} e^{7 x}

= \frac{8}{7} e^{7 x}

Add a constant to the solution

= \frac{8}{7} e^{7 x} + C

x \to 1 lim (π x cos (π) x)

\int e^{x} a - b e^{x} d x

y^{^{''}} + y^{^{'}} + 2 y = 0

\frac{d}{d x} ((5 x^{2} - 9) (8 x + 3))

(9.7) (3)