What is the integral of e^{2x}-e^x ?

The integral of e^{2x}-e^x is 1/2 e^{2x}-e^x+C

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integral of e^{2x}-e^x

\int e^{2 x} - e^{x} d x

\frac{1}{2} e^{2 x} - e^{x} + C

Solution steps

\int e^{2 x} - e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{2 x} d x - \int e^{x} d x

\int e^{2 x} d x = \frac{1}{2} e^{2 x}

\int e^{x} d x = e^{x}

= \frac{1}{2} e^{2 x} - e^{x}

Add a constant to the solution

= \frac{1}{2} e^{2 x} - e^{x} + C

\frac{a}{s + a}

\int 4 x^{3} d x

\frac{d}{d x} (\frac{1}{9 x})

\int x a^{x} d x

\int \frac{x ^{2}}{( 196 + x ^{2} ) ^{2}} d x

What is the integral of e^{2x}-e^x ?
The integral of e^{2x}-e^x is 1/2 e^{2x}-e^x+C