What is (\partial)/(\partial x)(xy-2x-2y-x^2-y^2) ?

The answer to (\partial)/(\partial x)(xy-2x-2y-x^2-y^2) is y-2x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(xy-2x-2y-x^2-y^2)

\frac{\partial}{\partial x} (x y - 2 x - 2 y - x^{2} - y^{2})

y - 2 x - 2

Solution steps

\frac{\partial}{\partial x} (x y - 2 x - 2 y - x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

= y - 2 - 0 - 2 x - 0

Simplify

= y - 2 x - 2

n = 1 \sum \infty \frac{2}{4 n ^{2} - 1}

\int \frac{x ^{2} - 1}{x ^{3}} d x

\frac{d y}{d t} = 6 e^{2 t - y}

\frac{d}{d x} (m x e^{n x^{2}})

\frac{d}{d x} (5 \cdot T g (T, x) (2 x^{3}) + \frac{2}{x ^{2}})

What is (\partial)/(\partial x)(xy-2x-2y-x^2-y^2) ?
The answer to (\partial)/(\partial x)(xy-2x-2y-x^2-y^2) is y-2x-2