What is the tangent of y= 5/(sqrt(x)),(1,5) ?

The tangent of y= 5/(sqrt(x)),(1,5) is y=-5/2 x+15/2

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tangent of y= 5/(sqrt(x)),(1,5)

tangent of

y = \frac{5}{x}, (1, 5)

y = - \frac{5}{2} x + \frac{15}{2}

Solution steps

Find the slope of

y = \frac{5}{x} : \frac{d y}{d x} = - \frac{5}{2 x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{5}{x}

(1, 5) : m = - \frac{5}{2}

Find the line with slope m=

- \frac{5}{2}

and passing through

(1, 5) : y = - \frac{5}{2} x + \frac{15}{2}

y = - \frac{5}{2} x + \frac{15}{2}

\int_{\frac{6}{5}}^{4} \frac{1}{1 - x ^{2}} d x

\int x^{\frac{3}{2}} (4 - 4 x) d x

x \to \infty lim (0.72 x)

\frac{d}{d x} (29 - x^{2} - 4 y^{2})

\frac{d}{d x} (4 cos (x) sin (x))

What is the tangent of y= 5/(sqrt(x)),(1,5) ?
The tangent of y= 5/(sqrt(x)),(1,5) is y=-5/2 x+15/2