What is the derivative of f(x)=(3x-10)(2x^2-x+1) ?

The derivative of f(x)=(3x-10)(2x^2-x+1) is 18x^2-46x+13

What is the first derivative of f(x)=(3x-10)(2x^2-x+1) ?

The first derivative of f(x)=(3x-10)(2x^2-x+1) is 18x^2-46x+13

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derivative of

f (x) = (3 x - 10) (2 x^{2} - x + 1)

18 x^{2} - 46 x + 13

Solution steps

\frac{d}{d x} ((3 x - 10) (2 x^{2} - x + 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x - 10, g = 2 x^{2} - x + 1

= \frac{d}{d x} (3 x - 10) (2 x^{2} - x + 1) + \frac{d}{d x} (2 x^{2} - x + 1) (3 x - 10)

\frac{d}{d x} (3 x - 10) = 3

\frac{d}{d x} (2 x^{2} - x + 1) = 4 x - 1

= 3 (2 x^{2} - x + 1) + (4 x - 1) (3 x - 10)

Simplify

3 (2 x^{2} - x + 1) + (4 x - 1) (3 x - 10) : 18 x^{2} - 46 x + 13

= 18 x^{2} - 46 x + 13

\int 17 e^{x} d x

\int \frac{a}{x ^{3}} d x

n = 1 \sum \infty 1^{n}

\int 2 a x d x

x \to 0 lim ((x + 1)^{\frac{1}{x}})

What is the derivative of f(x)=(3x-10)(2x^2-x+1) ?
The derivative of f(x)=(3x-10)(2x^2-x+1) is 18x^2-46x+13
What is the first derivative of f(x)=(3x-10)(2x^2-x+1) ?
The first derivative of f(x)=(3x-10)(2x^2-x+1) is 18x^2-46x+13