What is the solution for x^3y^{'''}-x^2y^{''}+2xy^'-2y=0 ?

The solution for x^3y^{'''}-x^2y^{''}+2xy^'-2y=0 is y=c_{1}x^2+c_{2}x+c_{3}ln(x)x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^3y^{'''}-x^2y^{''}+2xy^'-2y=0

x^{3} y^{^{'''}} - x^{2} y^{^{''}} + 2 x y^{^{'}} - 2 y = 0

y = c_{1} x^{2} + c_{2} x + c_{3} ln (x) x

Solution steps

x^{3} y^{'''} (x) - x^{2} y^{''} (x) + 2 x y^{'} (x) - 2 y = 0

Solve linear ODE:

y = c_{1} x^{2} + c_{2} x + c_{3} ln (x) x

y = c_{1} x^{2} + c_{2} x + c_{3} ln (x) x

x \to - \infty lim (e^{3 x} (2 - x))

\int \frac{x x + x}{x ^{2}} d x

\int (\frac{3}{x} + \frac{5}{x ^{2}}) d x

3 sin (5 t + 45)

\int \frac{( x ^{7} + 3 x ^{5} - 2 x ^{3} - 4 )}{x ^{3}} d x

What is the solution for x^3y^{'''}-x^2y^{''}+2xy^'-2y=0 ?
The solution for x^3y^{'''}-x^2y^{''}+2xy^'-2y=0 is y=c_{1}x^2+c_{2}x+c_{3}ln(x)x