What is the d/(d{r)}(sqrt({r)}+\sqrt[7]{{r}}) ?

The d/(d{r)}(sqrt({r)}+\sqrt[7]{{r}}) is 1/(2sqrt({r))}+1/(7{r)^{6/7}}

What is the first d/(d{r)}(sqrt({r)}+\sqrt[7]{{r}}) ?

The first d/(d{r)}(sqrt({r)}+\sqrt[7]{{r}}) is 1/(2sqrt({r))}+1/(7{r)^{6/7}}

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Popular >

\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d r} (r) = \frac{1}{2 r}

= \frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

\frac{x ^{2}}{7 + x}

\frac{d}{d x} (x (3 x + 5)^{3})

\int x (3 + x^{2})^{10} d x

\int (\frac{1}{x} + cot (x)) d x

\int \frac{5}{x ^{2} - 4 x + 8} d x

What is the d/(d{r)}(sqrt({r)}+\sqrt[7]{{r}}) ?
The d/(d{r)}(sqrt({r)}+\sqrt[7]{{r}}) is 1/(2sqrt({r))}+1/(7{r)^{6/7}}
What is the first d/(d{r)}(sqrt({r)}+\sqrt[7]{{r}}) ?
The first d/(d{r)}(sqrt({r)}+\sqrt[7]{{r}}) is 1/(2sqrt({r))}+1/(7{r)^{6/7}}