What is the integral from 0 to pi of 16sin(x) ?

The integral from 0 to pi of 16sin(x) is 32

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integral from 0 to pi of 16sin(x)

\int_{0}^{π} 16 sin (x) d x

32

Solution steps

\int_{0}^{π} 16 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 16 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 16 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 16 \cdot 2

Simplify

= 32

y^{^{''}} - y^{^{'}} + 20 y = 0

x \to 3 + lim (\frac{5}{x - 3})

(x - 2)^{6}

x \to 1 lim (3 x - 2)

\int \frac{( sin ( x ) ) ^{3}}{1 + ( cos ( x ) ) ^{3}} d x

What is the integral from 0 to pi of 16sin(x) ?
The integral from 0 to pi of 16sin(x) is 32