What is the derivative of \sqrt[3]{x}ln(x) ?

The derivative of \sqrt[3]{x}ln(x) is (ln(x))/(3x^{2/3)}+1/(x^{2/3)}

What is the first derivative of \sqrt[3]{x}ln(x) ?

The first derivative of \sqrt[3]{x}ln(x) is (ln(x))/(3x^{2/3)}+1/(x^{2/3)}

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\frac{ln ( x )}{3 x ^{\frac{2}{3}}} + \frac{1}{x ^{\frac{2}{3}}}

Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

Simplify

= \frac{ln ( x )}{3 x ^{\frac{2}{3}}} + \frac{1}{x ^{\frac{2}{3}}}

\int \frac{2}{X} d X

f (x) = 5 e^{5 x}

\int \frac{x ^{3}}{x ^{3} - 1} d x

\int 2 x y^{2} + 3 x^{2} d x

What is the derivative of \sqrt[3]{x}ln(x) ?
The derivative of \sqrt[3]{x}ln(x) is (ln(x))/(3x^{2/3)}+1/(x^{2/3)}
What is the first derivative of \sqrt[3]{x}ln(x) ?
The first derivative of \sqrt[3]{x}ln(x) is (ln(x))/(3x^{2/3)}+1/(x^{2/3)}