What is the derivative of y=3x^2+3x-5 ?

The derivative of y=3x^2+3x-5 is 6x+3

What is the first derivative of y=3x^2+3x-5 ?

The first derivative of y=3x^2+3x-5 is 6x+3

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derivative of

y = 3 x^{2} + 3 x - 5

6 x + 3

Solution steps

\frac{d}{d x} (3 x^{2} + 3 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 6 x + 3 - 0

Simplify

= 6 x + 3

\int \frac{1}{4 ( x ^{2} + 1 )} d x

\int cos (x) - 5 sin (x) d x

\frac{d}{d x} (7 x + 3)

\frac{d}{d x} (x^{x^{4}})

\int \frac{1}{4 + x ^{2}} d x

What is the derivative of y=3x^2+3x-5 ?
The derivative of y=3x^2+3x-5 is 6x+3
What is the first derivative of y=3x^2+3x-5 ?
The first derivative of y=3x^2+3x-5 is 6x+3