What is the derivative of 1/pi sin(pix) ?

The derivative of 1/pi sin(pix) is cos(pix)

What is the first derivative of 1/pi sin(pix) ?

The first derivative of 1/pi sin(pix) is cos(pix)

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\frac{d}{d x} (\frac{1}{π} sin (π x))

cos (π x)

Solution steps

\frac{d}{d x} (\frac{1}{π} sin (π x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{π} \frac{d}{d x} (sin (π x))

Apply the chain rule:

cos (π x) \frac{d}{d x} (π x)

= cos (π x) \frac{d}{d x} (π x)

\frac{d}{d x} (π x) = π

= \frac{1}{π} cos (π x) π

Simplify

\frac{1}{π} cos (π x) π : cos (π x)

= cos (π x)

x \to 5 lim (10 x + 35)

\frac{d}{d x} (ln (arcsin (x^{2})))

\int (x^{3} - 6 x) d x

\frac{d}{d x} (x^{3} - 6 x^{2} - 15 x + 40)

x \to 0 lim (- \frac{7}{1 - 7 x})

What is the derivative of 1/pi sin(pix) ?
The derivative of 1/pi sin(pix) is cos(pix)
What is the first derivative of 1/pi sin(pix) ?
The first derivative of 1/pi sin(pix) is cos(pix)