What is the solution for (x+y)dx+(x+2y)dy=0 ?

The solution for (x+y)dx+(x+2y)dy=0 is y=(-x+sqrt(-x^2+c_{1)})/2 ,y=-(x+sqrt(-x^2+c_{1)})/2

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(x+y)dx+(x+2y)dy=0

(x + y) d x + (x + 2 y) d y = 0

y = \frac{- x + - x ^{2} + c _{1}}{2}, y = - \frac{x + - x ^{2} + c _{1}}{2}

Solution steps

(x + y) d x + (x + 2 y) d y = 0

Solve exact ODE:

y = \frac{- x + - x ^{2} + c _{1}}{2}, y = - \frac{x + - x ^{2} + c _{1}}{2}

y = \frac{- x + - x ^{2} + c _{1}}{2}, y = - \frac{x + - x ^{2} + c _{1}}{2}

\int_{2}^{6} \frac{1}{x - 2} d x

x \to \infty lim (ln (+ x))

\frac{( 2 x + 3 )}{( x ^{2} + 1 )}

\frac{\partial}{\partial x} (1.679 \cdot 0.899 \cdot 0.899)

4 x + y^{2} = 32, x = y

What is the solution for (x+y)dx+(x+2y)dy=0 ?
The solution for (x+y)dx+(x+2y)dy=0 is y=(-x+sqrt(-x^2+c_{1)})/2 ,y=-(x+sqrt(-x^2+c_{1)})/2