What is the solution for (9x+1)y^2(dy)/(dx)+2x^2+3y^3=0 ?

The solution for (9x+1)y^2(dy)/(dx)+2x^2+3y^3=0 is y=\sqrt[3]{-(2x^3)/(9x+1)+(c_{1})/(9x+1)}

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(9x+1)y^2(dy)/(dx)+2x^2+3y^3=0

(9 x + 1) y^{2} \frac{d y}{d x} + 2 x^{2} + 3 y^{3} = 0

Solution steps

(9 x + 1) y^{2} \frac{d y}{d x} + 2 x^{2} + 3 y^{3} = 0

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What is the solution for (9x+1)y^2(dy)/(dx)+2x^2+3y^3=0 ?
The solution for (9x+1)y^2(dy)/(dx)+2x^2+3y^3=0 is y=\sqrt[3]{-(2x^3)/(9x+1)+(c_{1})/(9x+1)}