What is the integral from 0 to 8 of x/4 ?

The integral from 0 to 8 of x/4 is 8

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integral from 0 to 8 of x/4

\int_{0}^{8} \frac{x}{4} d x

8

Solution steps

\int_{0}^{8} \frac{x}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{8} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{8}

= \frac{1}{4} [\frac{x ^{2}}{2}]_{0}^{8}

Compute the boundaries:

32

= \frac{1}{4} \cdot 32

Simplify

= 8

x \to - 7 lim (\frac{x + 2}{x})

\int 64 - 4 x^{2} d x

\int 3 w 4 - w^{2} d w

\frac{\partial}{\partial x} (e^{y} + x + x^{4} + 5)

5 + 2 x, \frac{( 15 + x )}{3}