What is the derivative of y=8x^5+10x^3-4 ?

The derivative of y=8x^5+10x^3-4 is 40x^4+30x^2

What is the first derivative of y=8x^5+10x^3-4 ?

The first derivative of y=8x^5+10x^3-4 is 40x^4+30x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 8 x^{5} + 10 x^{3} - 4

40 x^{4} + 30 x^{2}

Solution steps

\frac{d}{d x} (8 x^{5} + 10 x^{3} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{5}) + \frac{d}{d x} (10 x^{3}) - \frac{d}{d x} (4)

\frac{d}{d x} (8 x^{5}) = 40 x^{4}

\frac{d}{d x} (10 x^{3}) = 30 x^{2}

\frac{d}{d x} (4) = 0

= 40 x^{4} + 30 x^{2} - 0

Simplify

= 40 x^{4} + 30 x^{2}

\frac{d}{d x} (lo g_{e} (\frac{3 + x}{3 - x}))

\frac{d}{d x} (\frac{8 x}{x ^{2} + 1})

\int 8 e^{- k x} d x

\int \frac{1}{x ^{2} + 6 x + 16} d x

x \to 0 lim (\frac{sin ( x )}{9 x})

What is the derivative of y=8x^5+10x^3-4 ?
The derivative of y=8x^5+10x^3-4 is 40x^4+30x^2
What is the first derivative of y=8x^5+10x^3-4 ?
The first derivative of y=8x^5+10x^3-4 is 40x^4+30x^2