What is the derivative of f(x)=ln(x^2+4) ?

The derivative of f(x)=ln(x^2+4) is (2x)/(x^2+4)

What is the first derivative of f(x)=ln(x^2+4) ?

The first derivative of f(x)=ln(x^2+4) is (2x)/(x^2+4)

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derivative of

f (x) = ln (x^{2} + 4)

\frac{2 x}{x ^{2} + 4}

Solution steps

\frac{d}{d x} (ln (x^{2} + 4))

Apply the chain rule:

\frac{1}{x ^{2} + 4} \frac{d}{d x} (x^{2} + 4)

= \frac{1}{x ^{2} + 4} \frac{d}{d x} (x^{2} + 4)

\frac{d}{d x} (x^{2} + 4) = 2 x

= \frac{1}{x ^{2} + 4} \cdot 2 x

Simplify

\frac{1}{x ^{2} + 4} \cdot 2 x : \frac{2 x}{x ^{2} + 4}

= \frac{2 x}{x ^{2} + 4}

y^{^{'}} - 2 y = 0

\frac{d}{d x} (ln (arctan (2 x)))

x \to 0 + lim (x^{8 s i n (x)})

\frac{d}{d x} (\frac{1}{2})

(x^{'} - 4 x)^{^{'}}

What is the derivative of f(x)=ln(x^2+4) ?
The derivative of f(x)=ln(x^2+4) is (2x)/(x^2+4)
What is the first derivative of f(x)=ln(x^2+4) ?
The first derivative of f(x)=ln(x^2+4) is (2x)/(x^2+4)