What is the derivative of f(x)=-4x^2+7x-5 ?

The derivative of f(x)=-4x^2+7x-5 is -8x+7

What is the first derivative of f(x)=-4x^2+7x-5 ?

The first derivative of f(x)=-4x^2+7x-5 is -8x+7

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derivative of

f (x) = - 4 x^{2} + 7 x - 5

- 8 x + 7

Solution steps

\frac{d}{d x} (- 4 x^{2} + 7 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (7 x) - \frac{d}{d x} (5)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (5) = 0

= - 8 x + 7 - 0

Simplify

= - 8 x + 7

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y^{^{''}} - y^{^{'}} - 6 y = 0

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What is the derivative of f(x)=-4x^2+7x-5 ?
The derivative of f(x)=-4x^2+7x-5 is -8x+7
What is the first derivative of f(x)=-4x^2+7x-5 ?
The first derivative of f(x)=-4x^2+7x-5 is -8x+7