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Popular >

derivative of g(x)=(x+2sqrt(x))e^x

Solution

derivative of

g (x) = (x + 2 x) e^{x}

Solution

(1 + \frac{1}{x}) e^{x} + e^{x} (x + 2 x)

Solution steps

\frac{d}{d x} ((x + 2 x) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 2 x, g = e^{x}

= \frac{d}{d x} (x + 2 x) e^{x} + \frac{d}{d x} (e^{x}) (x + 2 x)

\frac{d}{d x} (x + 2 x) = 1 + \frac{1}{x}

\frac{d}{d x} (e^{x}) = e^{x}

= (1 + \frac{1}{x}) e^{x} + e^{x} (x + 2 x)

Popular Examples

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\frac{d ^{3}}{d x ^{3}} (\frac{1}{x ^{2} + 1})

tangent of 8x^2+3x-7 tangent of

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\int_{- 1}^{1} (x + 1) (x + 2) (x + 3) d x

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8 (e^{0} cos (0) - e^{0} sin (0))

Frequently Asked Questions (FAQ)

What is the derivative of g(x)=(x+2sqrt(x))e^x ?
The derivative of g(x)=(x+2sqrt(x))e^x is (1+1/(sqrt(x)))e^x+e^x(x+2sqrt(x))
What is the first derivative of g(x)=(x+2sqrt(x))e^x ?
The first derivative of g(x)=(x+2sqrt(x))e^x is (1+1/(sqrt(x)))e^x+e^x(x+2sqrt(x))