What is the integral of (x+2)(x-1) ?

The integral of (x+2)(x-1) is (x^3)/3+(x^2)/2-2x+C

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integral of (x+2)(x-1)

\int (x + 2) (x - 1) d x

\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + C

Solution steps

\int (x + 2) (x - 1) d x

Expand

(x + 2) (x - 1) : x^{2} + x - 2

= \int x^{2} + x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int x d x - \int 2 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int x d x = \frac{x ^{2}}{2}

\int 2 d x = 2 x

= \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x

Add a constant to the solution

= \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + C

x \to 0 - lim (x^{9} - \frac{1}{x})

\int (9 x + 11) e^{x} d x

\int \frac{1}{x 1 + 3 x} d x

\int \frac{x}{x ^{2} - 1} d x

x \to 3 lim (x + 1 - 2)

What is the integral of (x+2)(x-1) ?
The integral of (x+2)(x-1) is (x^3)/3+(x^2)/2-2x+C