What is the integral from-2 to 1 of (x-6|x|) ?

The integral from-2 to 1 of (x-6|x|) is -33/2

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integral from-2 to 1 of (x-6|x|)

\int_{- 2}^{1} (x - 6 ∣ x ∣) d x

- \frac{33}{2}

Decimal Notation

- 16.5

Solution steps

\int_{- 2}^{1} x - 6 ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 2}^{0} x - 6 (- x) d x + \int_{0}^{1} x - 6 x d x

\int_{- 2}^{0} x - 6 (- x) d x = - 14

\int_{0}^{1} x - 6 x d x = - \frac{5}{2}

= - 14 - \frac{5}{2}

Simplify

- 14 - \frac{5}{2} : - \frac{33}{2}

= - \frac{33}{2}

x \to 0 lim (- x^{4})

y^{^{''}} + 4 y = x - \frac{x ^{2}}{20}

\frac{d}{d x} (ln (\frac{x ^{4}}{( 3 x - 4 ) ^{2}}))

2 π x^{2}

y^{^{'}} + \frac{1}{200 + t} y = 0

What is the integral from-2 to 1 of (x-6|x|) ?
The integral from-2 to 1 of (x-6|x|) is -33/2