What is the integral from 2 to 4 of 2/x-1/8 x ?

The integral from 2 to 4 of 2/x-1/8 x is 2ln(2)-3/4

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integral from 2 to 4 of 2/x-1/8 x

\int_{2}^{4} \frac{2}{x} - \frac{1}{8} x d x

2 ln (2) - \frac{3}{4}

Decimal Notation

0.63629 \dots

Solution steps

\int_{2}^{4} \frac{2}{x} - \frac{1}{8} x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} \frac{2}{x} d x - \int_{2}^{4} \frac{1}{8} x d x

\int_{2}^{4} \frac{2}{x} d x = 2 ln (2)

\int_{2}^{4} \frac{1}{8} x d x = \frac{3}{4}

= 2 ln (2) - \frac{3}{4}

y = - 8 x^{3} + 9 x^{2} + 6 x - 5

n = 0 \sum \infty \frac{3 ^{n}}{n ^{3}}

6 y^{^{'}} = y^{2}

n = 2 \sum \infty \frac{2}{n ^{3} - n}

\frac{d y}{d t} = 0.2 \cdot (y - sin (t)) + cos (t)

What is the integral from 2 to 4 of 2/x-1/8 x ?
The integral from 2 to 4 of 2/x-1/8 x is 2ln(2)-3/4