What is the tangent of y=5x-2x^2,(-3,-33) ?

The tangent of y=5x-2x^2,(-3,-33) is y=17x+18

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tangent of y=5x-2x^2,(-3,-33)

tangent of

y = 5 x - 2 x^{2}, (- 3, - 33)

y = 17 x + 18

Solution steps

Find the slope of

y = 5 x - 2 x^{2} : \frac{d y}{d x} = 5 - 4 x

Compute the slope of

y = 5 x - 2 x^{2}

(- 3, - 33) : m = 17

Find the line with slope m=

17

and passing through

(- 3, - 33) : y = 17 x + 18

y = 17 x + 18

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What is the tangent of y=5x-2x^2,(-3,-33) ?
The tangent of y=5x-2x^2,(-3,-33) is y=17x+18