What is (\partial)/(\partial x)(cos(sin(x^2))) ?

The answer to (\partial)/(\partial x)(cos(sin(x^2))) is -sin(sin(x^2))cos(x^2)*2x

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(\partial)/(\partial x)(cos(sin(x^2)))

\frac{\partial}{\partial x} (cos (sin (x^{2})))

- sin (sin (x^{2})) cos (x^{2}) \cdot 2 x

Solution steps

\frac{\partial}{\partial x} (cos (sin (x^{2})))

Apply the chain rule:

- sin (sin (x^{2})) \frac{\partial}{\partial x} (sin (x^{2}))

= - sin (sin (x^{2})) \frac{\partial}{\partial x} (sin (x^{2}))

\frac{\partial}{\partial x} (sin (x^{2})) = cos (x^{2}) \cdot 2 x

= - sin (sin (x^{2})) cos (x^{2}) \cdot 2 x

\frac{d}{d v} (ln (cosh (2 v)) - \frac{1}{2} tanh^{2} (2 v))

\frac{10}{s ( s + 1 )}

\frac{d}{d x} (\frac{f ( x )}{x ^{2}})

\frac{d}{d x} (3 x^{4} - 1)

\int (\frac{x ^{2} - x}{x ^{3} - 6 x ^{2} + 11 x - 6}) d x

What is (\partial)/(\partial x)(cos(sin(x^2))) ?
The answer to (\partial)/(\partial x)(cos(sin(x^2))) is -sin(sin(x^2))cos(x^2)*2x