What is the sum from n=0 to infinity of n-1 ?

The sum from n=0 to infinity of n-1 is diverges

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sum from n=0 to infinity of n-1

n = 0 \sum \infty n - 1

diverges

Solution steps

n = 0 \sum \infty n - 1

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d x} (ln^{2} (\frac{x}{3}))

\int \frac{1}{3 y} d y

\int (\frac{tan ( x )}{cos ^{2} ( x )}) d x

\int x (2 x + 1) d x

n = 1 \sum \infty \frac{1}{2 n + 4}

What is the sum from n=0 to infinity of n-1 ?
The sum from n=0 to infinity of n-1 is diverges