What is the integral of 1/(sin(x)sin(2x)) ?

The integral of 1/(sin(x)sin(2x)) is 1/2 (-csc(x)+ln|tan(x)+sec(x)|)+C

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integral of 1/(sin(x)sin(2x))

\int \frac{1}{sin ( x ) sin ( 2 x )} d x

\frac{1}{2} (- csc (x) + ln ∣ tan (x) + sec (x) ∣) + C

Solution steps

\int \frac{1}{sin ( x ) sin ( 2 x )} d x

Rewrite using trig identities

= \int \frac{1}{2 sin ^{2} ( x ) cos ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{sin ^{2} ( x ) cos ( x )} d x

Rewrite using trig identities

= \frac{1}{2} \cdot \int \frac{csc ^{2} ( x )}{cos ( x )} d x

Apply Integration By Parts

: - csc (x) - \int - sec (x) d x

= \frac{1}{2} (- csc (x) - \int - sec (x) d x)

\int - sec (x) d x = - ln ∣ tan (x) + sec (x) ∣

= \frac{1}{2} (- csc (x) - (- ln ∣ tan (x) + sec (x) ∣))

Simplify

= \frac{1}{2} (- csc (x) + ln ∣ tan (x) + sec (x) ∣)

Add a constant to the solution

= \frac{1}{2} (- csc (x) + ln ∣ tan (x) + sec (x) ∣) + C

\int 2 x (x^{2} + 2)^{- 5} d x

x^{5} y^{^{'}} + y^{5} = 0

x \to - 1 lim (e^{0})

\frac{d}{d x} (\frac{π}{( 3 x ) ^{2}})

\frac{d y}{d x} = 5 + y - 5 x + 8

What is the integral of 1/(sin(x)sin(2x)) ?
The integral of 1/(sin(x)sin(2x)) is 1/2 (-csc(x)+ln|tan(x)+sec(x)|)+C