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Popular >

x^2y^'=y^2+xy

Solution

x^{2} y^{^{'}} = y^{2} + x y

Solution

y = \frac{x}{- ln ( x ) + c _{1}}

Solution steps

x^{2} y^{'} (x) = y^{2} + x y

Solve Bernoulli ODE:

y = \frac{x}{- ln ( x ) + c _{1}}

y = \frac{x}{- ln ( x ) + c _{1}}

Popular Examples

slope of (3,3),(-3,-1)slope

(3, 3), (- 3, - 1)

integral of 3/(t^5)

\int \frac{3}{t ^{5}} d t

limit as x approaches 2-of 2-x

x \to 2 - lim (2 - x)

derivative of (5x^3-7^8)

\frac{d}{d x} ((5 x^{3} - 7)^{8})

(\partial)/(\partial x)(x^2+17.5xy-y^2)

\frac{\partial}{\partial x} (x^{2} + 17.5 x y - y^{2})

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'=y^2+xy ?
The solution for x^2y^'=y^2+xy is y= x/(-ln(x)+c_{1)}