What is the sum from n=0 to infinity of (e/pi)^n ?

The sum from n=0 to infinity of (e/pi)^n is converges

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sum from n=0 to infinity of (e/pi)^n

n = 0 \sum \infty (\frac{e}{π})^{n}

converges

Solution steps

n = 0 \sum \infty (\frac{e}{π})^{n}

Apply Series Ratio Test:

converges

= converges

\int cot (3 x) csc^{4} (3 x) d x

\int 45

f (x) = 3 x^{4}, at x = - 2, 48

(e^{- 2 t} - 1)^{2}

(1 - x^{2}) y^{^{''}} - 2 x y^{^{'}} + 2 y = 0

What is the sum from n=0 to infinity of (e/pi)^n ?
The sum from n=0 to infinity of (e/pi)^n is converges