What is the integral of sin(x)sec^2(x) ?

The integral of sin(x)sec^2(x) is sec(x)+C

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integral of sin(x)sec^2(x)

\int sin (x) sec^{2} (x) d x

sec (x) + C

Solution steps

\int sin (x) sec^{2} (x) d x

Rewrite using trig identities

= \int sin (x) (1 + tan^{2} (x)) d x

Apply Integration By Parts

: - sec (x) - \int - 2 sec (x) tan (x) d x

= - sec (x) - \int - 2 sec (x) tan (x) d x

\int - 2 sec (x) tan (x) d x = - 2 sec (x)

= - sec (x) - (- 2 sec (x))

Simplify

= sec (x)

Add a constant to the solution

= sec (x) + C

\frac{\partial}{\partial x} (4 x^{3} + 4 x y^{2})

e^{- 3 t}

(t^{2} + 16) (\frac{d x}{d t}) = (x^{2} + 25), x (0) = 5

x \to 0 lim ((1 - 5 x)^{\frac{1}{x}})

\int tan (x) (sec (x))^{4} d x

What is the integral of sin(x)sec^2(x) ?
The integral of sin(x)sec^2(x) is sec(x)+C