What is (\partial)/(\partial x)(3+200x^2+300y^2) ?

The answer to (\partial)/(\partial x)(3+200x^2+300y^2) is 400x

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(\partial)/(\partial x)(3+200x^2+300y^2)

\frac{\partial}{\partial x} (3 + 200 x^{2} + 300 y^{2})

400 x

Solution steps

\frac{\partial}{\partial x} (3 + 200 x^{2} + 300 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3) + \frac{\partial}{\partial x} (200 x^{2}) + \frac{\partial}{\partial x} (300 y^{2})

\frac{\partial}{\partial x} (3) = 0

\frac{\partial}{\partial x} (200 x^{2}) = 400 x

\frac{\partial}{\partial x} (300 y^{2}) = 0

= 0 + 400 x + 0

Simplify

= 400 x

f (x) = \frac{( 2 x - 1 )}{x + 3}, at x = 2

f (x) = (2 x - 4)^{4} (x^{2} + x + 1)^{5}

\frac{\partial}{\partial x} (\frac{y}{2 - x})

f (x) = \frac{4 x - 1}{x + 5}

What is (\partial)/(\partial x)(3+200x^2+300y^2) ?
The answer to (\partial)/(\partial x)(3+200x^2+300y^2) is 400x