What is (\partial)/(\partial t)(t^2x-t) ?

The answer to (\partial)/(\partial t)(t^2x-t) is 2xt-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial t)(t^2x-t)

\frac{\partial}{\partial t} (t^{2} x - t)

2 x t - 1

Solution steps

\frac{\partial}{\partial t} (t^{2} x - t)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (t^{2} x) - \frac{\partial}{\partial t} (t)

\frac{\partial}{\partial t} (t^{2} x) = 2 x t

\frac{\partial}{\partial t} (t) = 1

= 2 x t - 1

\int \frac{x}{x ^{2} + 9} d x

6 t^{3} + 5 cos (2 t)

\frac{d}{d x} (x^{2} 8 x - 5)

n = 0 \sum \infty 4 (\frac{1}{10})^{n}

t^{2} y^{^{'}} + t y = 7

What is (\partial)/(\partial t)(t^2x-t) ?
The answer to (\partial)/(\partial t)(t^2x-t) is 2xt-1