What is the derivative of ln(1-4x) ?

The derivative of ln(1-4x) is -4/(1-4x)

What is the first derivative of ln(1-4x) ?

The first derivative of ln(1-4x) is -4/(1-4x)

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\frac{d}{d x} (ln (1 - 4 x))

- \frac{4}{1 - 4 x}

Solution steps

\frac{d}{d x} (ln (1 - 4 x))

Apply the chain rule:

\frac{1}{1 - 4 x} \frac{d}{d x} (1 - 4 x)

= \frac{1}{1 - 4 x} \frac{d}{d x} (1 - 4 x)

\frac{d}{d x} (1 - 4 x) = - 4

= \frac{1}{1 - 4 x} (- 4)

Simplify

\frac{1}{1 - 4 x} (- 4) : - \frac{4}{1 - 4 x}

= - \frac{4}{1 - 4 x}

x + 10

\frac{s + 3.3}{s + 1}

\frac{d}{d x} (lo g_{10} (x^{2} - 5 x))

y = x (x - 6)^{2}

e^{- 5 x} + e^{3 x}

What is the derivative of ln(1-4x) ?
The derivative of ln(1-4x) is -4/(1-4x)
What is the first derivative of ln(1-4x) ?
The first derivative of ln(1-4x) is -4/(1-4x)