What is area (x^2-4),y=0,x=-4,x=3 ?

The answer to area (x^2-4),y=0,x=-4,x=3 is 71/3

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area (x^2-4),y=0,x=-4,x=3

area

(x^{2} - 4), y = 0, x = - 4, x = 3

\frac{71}{3}

Decimal Notation

23.66666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{3} x^{2} - 4 d x

Solve

\int_{- 4}^{3} x^{2} - 4 d x : \frac{71}{3}

The area is:

= \frac{71}{3}

\int \frac{e ^{5 s i n (x)}}{sec ( x )} d x

\frac{d}{d x} (\frac{( 3 x - 5 ) ^{3}}{( 2 x ^{2} + 1 ) ^{4}})

\frac{\partial}{\partial y} (y)

y^{^{''}} - 2 y^{^{'}} - 48 y = 0

\int \frac{1}{9 e ^{- 7 x} + e ^{7 x}} d x

What is area (x^2-4),y=0,x=-4,x=3 ?
The answer to area (x^2-4),y=0,x=-4,x=3 is 71/3