What is (\partial)/(\partial x)(-x^2y+4) ?

The answer to (\partial)/(\partial x)(-x^2y+4) is -2xy

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(\partial)/(\partial x)(-x^2y+4)

\frac{\partial}{\partial x} (- x^{2} y + 4)

- 2 x y

Solution steps

\frac{\partial}{\partial x} (- x^{2} y + 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x^{2} y) + \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

\frac{\partial}{\partial x} (4) = 0

= - 2 y x + 0

Simplify

= - 2 x y

\frac{d}{d x} (25 - x^{2} - y^{2} - z^{2})

\frac{\partial}{\partial x} (x^{2} y e^{x - z})

\frac{1}{1 + s} \cdot \frac{8}{s}

\int \frac{e ^{u}}{( 1 - e ^{u} ) ^{2}} d u

\frac{d y}{d x} = y^{2} (4 - e^{x})

What is (\partial)/(\partial x)(-x^2y+4) ?
The answer to (\partial)/(\partial x)(-x^2y+4) is -2xy