What is the solution for (-16xy^2+3y)+(-16x^2y+3x)y^'=0 ?

The solution for (-16xy^2+3y)+(-16x^2y+3x)y^'=0 is y=(c_{1})/x

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(-16xy^2+3y)+(-16x^2y+3x)y^'=0

(- 16 x y^{2} + 3 y) + (- 16 x^{2} y + 3 x) y^{^{'}} = 0

y = \frac{c _{1}}{x}

Solution steps

(- 16 x y^{2} + 3 y) + (- 16 x^{2} y + 3 x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

x^{2} + x y + 2 y^{2} = 18, (3, - 3)

\int \frac{x}{x ^{2} + 6 x + 13} d x

\int x e^{- x} sin (x) d x

x \to - \infty lim (x^{4} e^{x})

\frac{d}{d x} (1 - 2 e^{3 x})

What is the solution for (-16xy^2+3y)+(-16x^2y+3x)y^'=0 ?
The solution for (-16xy^2+3y)+(-16x^2y+3x)y^'=0 is y=(c_{1})/x