What is the derivative of 1-(x^2+y^2^{1/3}) ?

The derivative of 1-(x^2+y^2^{1/3}) is -(2x+2y\frac{dy)/(dx)}{3(x^2+y^2)^{2/3}}

What is the first derivative of 1-(x^2+y^2^{1/3}) ?

The first derivative of 1-(x^2+y^2^{1/3}) is -(2x+2y\frac{dy)/(dx)}{3(x^2+y^2)^{2/3}}

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\frac{d}{d x} (1 - (x^{2} + y^{2})^{\frac{1}{3}})

- \frac{2 x + 2 y \frac{d y}{d x}}{3 ( x ^{2} + y ^{2} ) ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (1 - (x^{2} + y^{2})^{\frac{1}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} ((x^{2} + y^{2})^{\frac{1}{3}})

\frac{d}{d x} (1) = 0

\frac{d}{d x} ((x^{2} + y^{2})^{\frac{1}{3}}) = \frac{2 x + 2 y \frac{d y}{d x}}{3 ( x ^{2} + y ^{2} ) ^{\frac{2}{3}}}

= 0 - \frac{2 x + 2 y \frac{d y}{d x}}{3 ( x ^{2} + y ^{2} ) ^{\frac{2}{3}}}

Simplify

= - \frac{2 x + 2 y \frac{d y}{d x}}{3 ( x ^{2} + y ^{2} ) ^{\frac{2}{3}}}

\int 4 x - 3 - x^{2} d x

\frac{\partial}{\partial x} (\frac{1}{x yz})

f (x) = - 8 x^{2} + 7 x

(x - 8 y) d x + 4 x d y = 0

\frac{1}{( s - 2 ) ( s - 1 )}

What is the derivative of 1-(x^2+y^2^{1/3}) ?
The derivative of 1-(x^2+y^2^{1/3}) is -(2x+2y\frac{dy)/(dx)}{3(x^2+y^2)^{2/3}}
What is the first derivative of 1-(x^2+y^2^{1/3}) ?
The first derivative of 1-(x^2+y^2^{1/3}) is -(2x+2y\frac{dy)/(dx)}{3(x^2+y^2)^{2/3}}