What is the solution for (y^'-e^{-t}+4)/y =-4,y(0)=3 ?

The solution for (y^'-e^{-t}+4)/y =-4,y(0)=3 is y= 1/(3e^t)-1+(11)/(3e^{4t)}

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(y^'-e^{-t}+4)/y =-4,y(0)=3

\frac{y ^{^{'}} - e ^{- t} + 4}{y} = - 4, y (0) = 3

y = \frac{1}{3 e ^{t}} - 1 + \frac{11}{3 e ^{4 t}}

Solution steps

\frac{y ^{'} ( t ) - e ^{- t} + 4}{y} = - 4

Solve linear ODE:

y = \frac{1}{3 e ^{t}} - 1 + \frac{11}{3 e ^{4 t}}

y = \frac{1}{3 e ^{t}} - 1 + \frac{11}{3 e ^{4 t}}

o f (o, y) y = \frac{π}{2}, (π, \frac{π}{2})

\frac{d}{d x} (arcsec (x^{2} + 1))

x \to \infty lim (3 x^{3} (e^{- \frac{2}{x ^{3}}} - 1))

\int π x cos (2 x) d x

n = 1 \sum \infty cos (\frac{1}{n ^{3}})

What is the solution for (y^'-e^{-t}+4)/y =-4,y(0)=3 ?
The solution for (y^'-e^{-t}+4)/y =-4,y(0)=3 is y= 1/(3e^t)-1+(11)/(3e^{4t)}