What is the derivative of sin(x-x) ?

The derivative of sin(x-x) is cos(x)-1

What is the first derivative of sin(x-x) ?

The first derivative of sin(x-x) is cos(x)-1

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\frac{d}{d x} (sin (x) - x)

cos (x) - 1

Solution steps

\frac{d}{d x} (sin (x) - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x)) - \frac{d x}{d x}

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d x}{d x} = 1

= cos (x) - 1

\frac{( 3 x ^{2} e ^{x} - 4 )}{x ^{2}}

\int \frac{t ^{3}}{1 - t ^{8}} d t

\int_{2}^{3} e^{1 - x} d x

\frac{\partial}{\partial y} (ln (y^{2} + 1))

\frac{d}{d x} (4 x^{2} - e^{x})

What is the derivative of sin(x-x) ?
The derivative of sin(x-x) is cos(x)-1
What is the first derivative of sin(x-x) ?
The first derivative of sin(x-x) is cos(x)-1