What is the derivative of 2^x*ln(2) ?

The derivative of 2^x*ln(2) is ln^2(2)*2^x

What is the first derivative of 2^x*ln(2) ?

The first derivative of 2^x*ln(2) is ln^2(2)*2^x

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derivative of

2^{x} \cdot ln (2)

ln^{2} (2) \cdot 2^{x}

Solution steps

\frac{d}{d x} (2^{x} ln (2))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln (2) \frac{d}{d x} (2^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= ln (2) \cdot 2^{x} ln (2)

Simplify

ln (2) \cdot 2^{x} ln (2) : ln^{2} (2) \cdot 2^{x}

= ln^{2} (2) \cdot 2^{x}

\frac{d}{d x} (e^{- x} cos (\frac{1}{2} x))

x \to 0 lim (x^{8 s i n (x)})

(x 1 - x^{2})^{^{'}}

\int \frac{sec ^{2} ( y )}{tan ( y )} d y

\frac{d}{d x} (sin^{2} (tan (4 x)))

What is the derivative of 2^x*ln(2) ?
The derivative of 2^x*ln(2) is ln^2(2)*2^x
What is the first derivative of 2^x*ln(2) ?
The first derivative of 2^x*ln(2) is ln^2(2)*2^x