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Popular >

cos^2(t)y^'=1

Solution

cos^{2} (t) y^{^{'}} = 1

Solution

y = tan (t) + c_{1}

Solution steps

cos^{2} (t) y^{'} (t) = 1

Isolate

y^{'} (t) : y^{'} (t) = \frac{1}{cos ^{2} ( t )}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{1}{cos ^{2} ( t )} d t

\int \frac{1}{cos ^{2} ( t )} d t = tan (t) + c_{1}

y = tan (t) + c_{1}

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\frac{d y}{d x} + \frac{2 x}{1 + x ^{2}} y = - 2 x y^{2}

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\int_{1}^{x} 2 (x - 1) d x

derivative of f(x)=arctan(x^{10})derivative of

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Frequently Asked Questions (FAQ)

What is the solution for cos^2(t)y^'=1 ?
The solution for cos^2(t)y^'=1 is y=tan(t)+c_{1}