What is the derivative of sqrt(2t) ?

The derivative of sqrt(2t) is 1/(sqrt(2)\sqrt{t)}

What is the first derivative of sqrt(2t) ?

The first derivative of sqrt(2t) is 1/(sqrt(2)\sqrt{t)}

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derivative of

2 t

\frac{1}{2 t}

Solution steps

\frac{d}{d t} (2 t)

Apply the chain rule:

\frac{1}{2 2 t} \frac{d}{d t} (2 t)

= \frac{1}{2 2 t} \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= \frac{1}{2 2 t} \cdot 2

Simplify

\frac{1}{2 2 t} \cdot 2 : \frac{1}{2 t}

= \frac{1}{2 t}

sec (\frac{π}{3}) tan (\frac{π}{3})

(11 x^{2} \cdot y - 13 x) d y = - (11 x y^{2} - 13 y) d x

\int_{0}^{1} (x^{2} + 3) e^{- x} d x

\int - y e^{y} d y

\frac{\partial}{\partial x} (x^{2} y + x y)

What is the derivative of sqrt(2t) ?
The derivative of sqrt(2t) is 1/(sqrt(2)\sqrt{t)}
What is the first derivative of sqrt(2t) ?
The first derivative of sqrt(2t) is 1/(sqrt(2)\sqrt{t)}