What is the integral of (ln(17x))^2 ?

The integral of (ln(17x))^2 is xln^2(17x)-2(xln(17x)-x)+C

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integral of (ln(17x))^2

\int (ln (17 x))^{2} d x

x ln^{2} (17 x) - 2 (x ln (17 x) - x) + C

Solution steps

\int (ln (17 x))^{2} d x

Apply Integration By Parts

: x ln^{2} (17 x) - \int 2 ln (17 x) d x

= x ln^{2} (17 x) - \int 2 ln (17 x) d x

\int 2 ln (17 x) d x = 2 (x ln (17 x) - x)

= x ln^{2} (17 x) - 2 (x ln (17 x) - x)

Add a constant to the solution

= x ln^{2} (17 x) - 2 (x ln (17 x) - x) + C

x \to \infty lim (\frac{8}{10})

f (x) = \frac{x ^{2} + 5}{x - 2}

\frac{d y}{d x} = \frac{1}{x}

n \to \infty lim (n x)

\frac{d y}{d t} + e^{t} y = 2 e^{t}

What is the integral of (ln(17x))^2 ?
The integral of (ln(17x))^2 is xln^2(17x)-2(xln(17x)-x)+C